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05-23-2003, 12:57 PM | #1 |
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Did I figure this out correctly (Planck's energy distribution formula).
I tried figuring this one out a while back. Here's my work:
http://www.angelfire.com/anime4/keyser_soze/planck.html Did I do okay, and did I get the right formula? |
05-23-2003, 01:05 PM | #2 |
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In your list of symbols, you have 2*pi=approx. 3.1416
Actually, it should be pi = approx. 3.1416 |
05-23-2003, 01:16 PM | #3 |
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Yikes. That's a typo. I'll go fix it real quick. I meant to put "2pi = 6.2832". Thanks for pointing that out.
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05-23-2003, 01:31 PM | #4 |
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Shouldn't it be 8*pi, since you are integrating over 4*pi steradians?
You said power per area per wavelength. |
05-23-2003, 01:50 PM | #5 |
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I dunno. I just got the formula and what the symbols and all in it mean off of a webpage and tried out a random wavelength and temperature. Did my source make an error?
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05-23-2003, 02:19 PM | #6 |
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From Radiative Processes in Astrophysics by Rybicki & Lightman.
Page 22 (the derivation is shown on pages 20 thru 22): B_lam(T) = 2hc^2/lam^5/[exp(hc/lam kT)-1] in units of energy/time/area/wavelength/steradian. If you want it in power/area/wavelength as you have, then you need to integrate over 4*pi steradians. From what webpage did you get the original formula? edit: Ah, I see where the confusion might lie. Page 19 of Rybicki & Lightman says that "the emergent flux from an istropically emitting surface is pi * Brightness", so that Flux = pi * B(T) That definition would account for your pi. |
05-23-2003, 06:19 PM | #7 |
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I can't remember exactly where I got that particular image from, but an identical formula with the same explanations for the symbols can be found here:
http://www.imsa.edu/edu/geophysics/a...y/planck1.html Is there a mistake in this source? If so, could you give me a source to the actual formula? I like figuring out things that I won't get actually taught until I go to college. |
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