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Old 04-19-2003, 02:07 PM   #11
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Quote:
Originally posted by Volker.Doormann
Permittivity and permeability of the free space are absolute physical constants in the universe and they are.

If you mean, (?) that there are also gains in dielectric or magnetic materials of these properties, that is true, but in an universe without matter (energy only), there still exist permittivity and permeability of the (matter-)free space as absolute physical constants.

Volker
Yes, but the permittivity of free space is zero, indicating that in free space the property does not exist.
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Old 04-19-2003, 02:42 PM   #12
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Originally posted by Majestyk
... the permittivity of free space is zero ..
I have learned that the permittivity of the free space is some more then zero, but 8.854187817E-12 F/m.

s. p.e.:
http://hyperphysics.phy-astr.gsu.edu...ic/elefie.html
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Old 04-19-2003, 02:51 PM   #13
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Originally posted by Volker.Doormann
I have learned that the permittivity of the free space is some more then zero, but 8.854187817E-12 F/m.

s. p.e.:
http://hyperphysics.phy-astr.gsu.edu...ic/elefie.html
ah, my mistake. Confused the relative representation of free space permittivity with the permittivity of free space.
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Old 04-19-2003, 03:05 PM   #14
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Originally posted by Majestyk
ah, my mistake. Confused the relative representation of free space permittivity with the permittivity of free space.
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Old 04-19-2003, 05:20 PM   #15
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Quote:
Originally posted by Shake
The only other instances where the might be free is in the case of virtual particle creation/annihilation in the vicinity of a black hole. This is an idea proposed by Hawking wherein a virtual particle/anti-particle pair is created very near the event horizon of a black hole. Normally, the pair would only exist a short time before annihilating each other and ceasing to exist. However, under these circumstances, one particle is sucked into the black hole and the other escapes! Anyone else care to clarify or expand on this idea?
It is my understanding that these vitual paricle pairs are produced everywhere in space (including inside our bodies), not just near the event horizons of black holes. Those that produce Hawking radiation are responsible for the evaporation of black holes, creating in the process "stable" virtual particles (an oxymoron, huh?) that don't annihilate immediately, perhaps producing anti-matter.
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Old 04-19-2003, 09:02 PM   #16
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Originally posted by Unbeliever
It is my understanding that these vitual paricle pairs are produced everywhere in space (including inside our bodies), not just near the event horizons of black holes. Those that produce Hawking radiation are responsible for the evaporation of black holes, creating in the process "stable" virtual particles (an oxymoron, huh?) that don't annihilate immediately, perhaps producing anti-matter.

I think that the CP violation is the main reason for the asymmetry of matter over its anti-matter counterparts. Anyway, what do you mean by "stable" virtual particles? Virtual particle with long lifetime?
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Old 04-19-2003, 09:16 PM   #17
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Quote:
Originally posted by Unbeliever
It is my understanding that these vitual paricle pairs are produced everywhere in space (including inside our bodies), not just near the event horizons of black holes. Those that produce Hawking radiation are responsible for the evaporation of black holes, creating in the process "stable" virtual particles (an oxymoron, huh?) that don't annihilate immediately, perhaps producing anti-matter.

:notworthy Hawking is god :notworthy

The creation of virtual pairs of particles does not violate the law of
conservation of mass-energy because these enigmatic quntum flux's only exist for brief periods of time, much less than the Planck time, 10^(-43) sec. There is a temporary suspension-violation of the law of conservation of mass-energy, but this violation occurs within the timescale of the uncertainty principle, DxDp >= hbar/2, and thus, has no impact on the observed macroscopic laws. The quantum vacuum is the ground state of energy for the Universe, the lowest possible level. It
allows for the "Casimir effect" and Hawking radiation.


The basic point concerning Hawking radiation, is that the idea of
"vacuum" and also the notion of particles loses their meaning in the presence of a dynamic quantum background. Incoming modes of the quantum field are redshifted while propagating through the collapsing geometry, which is why the quantum state of the outgoing modes is different. The incoming state is a vacuum state while the outgoing state contains particles.

The negative energy flux decreases the mass of the black hole, and becomes equivalent to a positive energy flux of Hawking radiation at infinity.

It seems that the vacuum expectation value of the energy-momentum of the quantum field is negative near the horizon, analogous to a flux of negative energy into the hole and gives the heuristic basis for the the pictorial interpretation of the black hole radiation, explained as one particle of a virtual pair falling into the black hole, and enabling the other partner to become real and escape to infinity, allowing it to be observed as Hawking radiation.

Temperature T, is constant on a body in thermal equilibrium and the surface gravity k, is constant on the horizon of a black hole. The area of the horizon is related to the measure of its entropy S.

dE = TdS - pdV + (mu)dN

dE = (kc^2)dA/(8piG) + (omega)dJ - (phi)dq

dS >= 0

dA >= 0

A temperature of absolute zero cannot be reached.

A surface gravity of zero cannot be reached.

Unruh's law:
Accelerating observers see themselves as bathed in a gas of hot
photons, with temperature proportional to their acceleration.


Space can be hypothesized as a type of conductor, yet not a type of "medium", lest we revive the "lumeniferous ether".

e is the permittivity of free space and u is the permeability of free
space, epsilon and mu respectively.

E = mc^2

c^2 = 1/(eu)

E/m = 1/(eu)

The ratio of ([total energy]/mass) = 1/(eu)

(eu) would of course remain "ivariant" while observing from inertial reference frames but the E and m values would individually vary, yet vary in tandem producing a constant "c"
or 1/(eu) .

1/(eu) = (Ds/Dt)^2 , Ds and Dt would also vary in tandem, depending upon relative velocity.

Ds/(eu)^(1/2) = Dt

It seems that the permittivity and permeability of free space would not change, thus the "curvature" of space-time is independent of the conductivity of electromagnetism in space.

The controversial physicist Lee Smolin, wrote this interesting idea in the book:

"Three Roads to Quantum Gravity"

Quote:

The one big clue we have is that the string stretched between two quarks behaves just like a line of magnetic flux in a superconductor. This suggests a simple hypothesis: perhaps empty space is very like a superconductor, except that what ends up discrete is the lines of force holding the colour charges of quarks together rather than the lines of magnetic flux. In this picture the lines of force between the coloured charges on the quarks are analogous to the electric rather than the magnetic field. So this hypothesis can be put very succinctly as follows: empty space is a colour electric superconductor.
Interesting. As a thought experiment, imagine a perfectly smooth homogenous liquid or "fluid" that stretches out to infinity.

The fluid has a small distortion or vortice moving in the fluid. How
can the speed of the "vortice" in the fluid be measured?

Only by inserting an object in the fluid and creating a relative frame of reference. That would be breaking the rules of course, because no outside elements can be introduced into the fluid. The only way to measure the speed of the vortice is by comparing its motion with another vortice.

If forces of nature are really just distortions in the space-time
fluid, then the motion of a space-time distortion can only be compared to the motion of another distortion. Yes, the luminiferous ether becomes superfluous. The vortice can represent matter-energy, which is just a distortion of space.

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Old 04-20-2003, 06:07 AM   #18
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Quote:
Originally posted by GPLindsey


Now, for every particle in the universe there is an anti-particle.

Come to think of it, in Feymann diagrams, for every particle moving forwards and backwards in time is the same antiparticle that is moving backwards and forwards in time respectively.
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Old 04-21-2003, 10:55 AM   #19
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Default cognito ergo sum

I think therefore everything exists
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Old 04-21-2003, 11:33 AM   #20
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Quote:
Originally posted by GPLindsey
Zero is nothing--the absence of value. But you can get to zero by adding positive and negative numbers that cancel each other out, such as 10 billion plus negative 10 billion.

Now, for every particle in the universe there is an anti-particle. In effect, there is a positive universe and a negative universe existing side by side. Therefore, to combine the two and describe the total universe conceptually as a mathematical formula, you would have to say that its value is zero, or nothing. Thus, to religious critics who beat up the nonreligious with the metaphysical question: "How can you have something from nothing?" The answer is simply that there really is NOTHING--the universe does not exist!
Good point. This is the basis of a whole new theory devised by Ronald Pearson, described here (among other places). Read with an open mind.
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