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04-19-2003, 02:07 PM | #11 | |
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04-19-2003, 02:42 PM | #12 | |
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s. p.e.: http://hyperphysics.phy-astr.gsu.edu...ic/elefie.html |
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04-19-2003, 02:51 PM | #13 | |
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04-19-2003, 03:05 PM | #14 | |
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Good Night from Germany - it's Midnight here. Volker |
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04-19-2003, 05:20 PM | #15 | |
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04-19-2003, 09:02 PM | #16 | |
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I think that the CP violation is the main reason for the asymmetry of matter over its anti-matter counterparts. Anyway, what do you mean by "stable" virtual particles? Virtual particle with long lifetime? |
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04-19-2003, 09:16 PM | #17 | ||
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:notworthy Hawking is god :notworthy The creation of virtual pairs of particles does not violate the law of conservation of mass-energy because these enigmatic quntum flux's only exist for brief periods of time, much less than the Planck time, 10^(-43) sec. There is a temporary suspension-violation of the law of conservation of mass-energy, but this violation occurs within the timescale of the uncertainty principle, DxDp >= hbar/2, and thus, has no impact on the observed macroscopic laws. The quantum vacuum is the ground state of energy for the Universe, the lowest possible level. It allows for the "Casimir effect" and Hawking radiation. The basic point concerning Hawking radiation, is that the idea of "vacuum" and also the notion of particles loses their meaning in the presence of a dynamic quantum background. Incoming modes of the quantum field are redshifted while propagating through the collapsing geometry, which is why the quantum state of the outgoing modes is different. The incoming state is a vacuum state while the outgoing state contains particles. The negative energy flux decreases the mass of the black hole, and becomes equivalent to a positive energy flux of Hawking radiation at infinity. It seems that the vacuum expectation value of the energy-momentum of the quantum field is negative near the horizon, analogous to a flux of negative energy into the hole and gives the heuristic basis for the the pictorial interpretation of the black hole radiation, explained as one particle of a virtual pair falling into the black hole, and enabling the other partner to become real and escape to infinity, allowing it to be observed as Hawking radiation. Temperature T, is constant on a body in thermal equilibrium and the surface gravity k, is constant on the horizon of a black hole. The area of the horizon is related to the measure of its entropy S. dE = TdS - pdV + (mu)dN dE = (kc^2)dA/(8piG) + (omega)dJ - (phi)dq dS >= 0 dA >= 0 A temperature of absolute zero cannot be reached. A surface gravity of zero cannot be reached. Unruh's law: Accelerating observers see themselves as bathed in a gas of hot photons, with temperature proportional to their acceleration. Space can be hypothesized as a type of conductor, yet not a type of "medium", lest we revive the "lumeniferous ether". e is the permittivity of free space and u is the permeability of free space, epsilon and mu respectively. E = mc^2 c^2 = 1/(eu) E/m = 1/(eu) The ratio of ([total energy]/mass) = 1/(eu) (eu) would of course remain "ivariant" while observing from inertial reference frames but the E and m values would individually vary, yet vary in tandem producing a constant "c" or 1/(eu) . 1/(eu) = (Ds/Dt)^2 , Ds and Dt would also vary in tandem, depending upon relative velocity. Ds/(eu)^(1/2) = Dt It seems that the permittivity and permeability of free space would not change, thus the "curvature" of space-time is independent of the conductivity of electromagnetism in space. The controversial physicist Lee Smolin, wrote this interesting idea in the book: "Three Roads to Quantum Gravity" Quote:
The fluid has a small distortion or vortice moving in the fluid. How can the speed of the "vortice" in the fluid be measured? Only by inserting an object in the fluid and creating a relative frame of reference. That would be breaking the rules of course, because no outside elements can be introduced into the fluid. The only way to measure the speed of the vortice is by comparing its motion with another vortice. If forces of nature are really just distortions in the space-time fluid, then the motion of a space-time distortion can only be compared to the motion of another distortion. Yes, the luminiferous ether becomes superfluous. The vortice can represent matter-energy, which is just a distortion of space. Chimp |
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04-20-2003, 06:07 AM | #18 | |
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Re: The universe does not exist
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Come to think of it, in Feymann diagrams, for every particle moving forwards and backwards in time is the same antiparticle that is moving backwards and forwards in time respectively. |
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04-21-2003, 10:55 AM | #19 |
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cognito ergo sum
I think therefore everything exists
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04-21-2003, 11:33 AM | #20 | |
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Re: The universe does not exist
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