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Old 09-26-2002, 06:02 AM   #31
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1. a(t) = v'(t) = d''(t)

2. (p -> q) -> (!q -> !p)

3. F = ma, if only because its finer points should be mandatory education for SUV owners.
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Old 09-26-2002, 07:02 AM   #32
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Quote:
Originally posted by Bialar Crais:
<strong>I vaguely remember my math teacher trying to bite my head of for suggesting that (-1)^0.5 = i...</strong>
Probably because in the complex plane, the square root isn't really a function until you fix a branch (i.e. (-i)^2 = -1, too.)

m.
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Old 09-26-2002, 07:11 AM   #33
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Quote:
Originally posted by trientalis:
<strong>This may be an odd question but in what way is e^iPi + 1 = 0 a "beautiful" equation? I've come across that equation before in "The Art of Mathematics" and the author's explanation didn't help. If any of the mathematically inclined out there could have a stab at explaining why the above equation is "beautiful" and not just interesting, I'd be ever so grateful.
And another thing: is the equation useful in any way, much as F = ma is useful? Is there a application for that equation? Or is it just a "beautiful" result?

Sorry to be overly, well, pathetically earnest. I'm not a mathematician but I am a lover of beauty. The beauty of mathematics is something I have yet to experience, much less understand. If you are a mathematician, I envy you for the beauty you see that I do not.

&lt;End of whine&gt;</strong>
It as was said, it relates five fundamental constants in the pure mathematics (e, i, pi, 0, 1) using the 4 fundamental operations (=, +, *, ^).

It's also a specific case of the equation e^(theta*i)=sin(theta)+i*cos(theta), where theta=pi, and is an absurdly useful equation. It's pretty much the foundation to all modern mathematics in communications, as it is vital to the math behind a fourier transform.
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Old 09-26-2002, 08:02 AM   #34
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Quote:
Originally posted by NialScorva:
<strong>
It's also a specific case of the equation e^(theta*i)=sin(theta)+i*cos(theta), </strong>
Actually, it is e^(theta*i)=cos(theta)+i*sin(theta)

Sorry about the nitpicking.
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Old 09-26-2002, 08:25 AM   #35
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Quote:
Originally posted by Abacus:
<strong>

Actually, it is e^(theta*i)=cos(theta)+i*sin(theta)

Sorry about the nitpicking.</strong>
D'oh!
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Old 09-26-2002, 11:46 AM   #36
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Hehe

My nitpick:


Nitpicking is important in maths. Every little symbol counts and altering anything however slightly can throw off a whole branch off mathematics...

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Old 09-26-2002, 01:16 PM   #37
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a^2 + b^2 = c^2 -Pythagoras

f=Ma - Newton

A=pi (r)^2
C=pi (d) - Unknown
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Old 09-26-2002, 01:18 PM   #38
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Quote:
Originally posted by MadMordigan:
<strong>
A=pi (r)^2
C=pi (d) - Unknown</strong>
Archimedes
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Old 09-26-2002, 02:19 PM   #39
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Quote:
Originally posted by Bloop:
<strong>Hehe

My nitpick:


Nitpicking is important in maths. Every little symbol counts and altering anything however slightly can throw off a whole branch off mathematics...

</strong>
Oh my gods you are sooo right. I'm working a Quantum Mechanics problem now using matrices. See what happens when you misplace a negative and are dealing with complex coefficients? That's right--you lose more hair. Argh.
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Old 09-26-2002, 02:45 PM   #40
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Since I work in radiation therapy:

1. The inverse square law

2. I = I(sub0)e^ux

oops, forgot the thread wanted three equations

3. linear quadratic formalisms such as

S= exp(-alphaD - Gbeta D^2)

are used to determine the survivability of tumor cells to radiation.

[ September 26, 2002: Message edited by: gilly54 ]</p>
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