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Old 12-08-2005, 05:11 AM   #1
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Default My Theory of Everything...

This is the theory of everything
It's just a circle representing true/average position, and the position of the mask/shell (of the desire to be separate from your reality)

Code:
digital/separating/deducing  Truth   nurturing God
                               |
Hate/Separation---pure imaginary/dream/confusion/detachment---Love/Union
                               |
satan                    False Truth      analogue/connecting/infering
BTW, if you feel too emotional (crying, fear) a good way of escaping back to your divine machine robot mind is to play solitare on the computer or maybe physically too...
Code:
    KQ
    |
98765432A
    |
    J
On the y axis is royalty and false royalty
On the x axis is separation and union/bliss

The horizontal middle is plain/practical and the y axis is true knowledge/class and false knowledge/class axis

Devil = J9 Nurturing God = KA

For technical details that gradually explain it, see:
http://www.nomoremrniceguy.com/forum...ead.php?t=6651

I'll eventually put horoscopes, emeagram, myers-brigs, etc on the picture. And I've got an idea for a colourful picture to represent all the concepts.
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Old 12-08-2005, 05:26 AM   #2
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Um, J5EQK501
1234E,
ergo sum?
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Old 12-08-2005, 05:27 AM   #3
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What a fabulous grasp of logic you have... that has completely disproven my theory!
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Old 12-08-2005, 05:37 AM   #4
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BTW, the true average/core could be in the positive imaginary axis +z (reality)
a false sabotaging average/core would be in the negative imaginary axis -z (fantasy)
x = 0 y = 0 z = 0 is where it is indeterminate - not love/hate (pleasure/pain) not true/false (valuable/worthless) not reality/imaginary (z axis)

It *seems* like I *might* have discovered the matrix... hmmm.... (I've got much more... just hold on a bit)

BTW, some people are so quick to dismiss this... but logically we're not certain that we aren't in some kind of matrix...

the digital mind = computer mind (virtual transistors)
the analogue mind = intuitive mind, but it seems to be a simple neural network
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Old 12-08-2005, 05:39 AM   #5
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http://www.newton.dep.anl.gov/newton...th/MATH067.HTM
Quote:
When talking about the complex plane, we measure the real part of a complex
number z along one axis (say, the x axis) which we call the real axis, and
the imaginary part [i.e., the coefficient of i = sqrt(-1)] along the other
axis, which we call the imaginary axis; and we write z = x + i*y. Just as
we can designate points in the plane by rectangular coordinates (x,y), we
can also use polar coordinates (r, theta). Recall the relationship between
these sets of coordinates: x = r*cos(theta), y = r*sin(theta). Substituting
these into the expression for z, we get
z = r*cos(theta) + i*r*sin(theta) = r*[cos(theta) + i*sin(theta)].
There is a result due to Euler which says
e^(i*theta) = cos(theta) + i*sin(theta). Thus, z = r*e^(i*theta).
This is often called the polar form of the complex number z. Without loss
of generality, we can require that r be non-negative. Note that the modulus
of e^(i*theta) = sqrt[cos^2(theta) + sin^2(theta)]
which equals 1 regardless of what theta is. Thus, the modulus of z is r.
Now to your question. Note that z^5 = r^5 * e^(i * 5 * theta). {The point
of going to the polar form is to exploit here the fact that
[e^(i * theta)]^5 = e^(i * 5 * theta).} We want to solve z^5 = 1, or
r^5 * e^(i * 5 * theta) = 1 + 0*i.
First, take modulus of both sides. This gives r^5 = 1. Since r is real and
non-negative, we must have r = 1. Putting that in, we now must solve
e^(i * 5 * theta) = 1 + 0*i. Converting back to sines and cosines and
matching up real and imaginary parts, we must solve cos(5 * theta) = 1 and
sin(5 * theta) = 0. It suffices to solve only the cosine equation, since
any solution to it will also solve the sine equation (but not conversely).
Thus, we get 5 * theta = 2 * k * pi, where k is any integer. The five
choices k = 0, 1, 2, 3, 4 give distinct solutions; thus, a complete
solution set (5 points) is r = 1 and theta = 0, 2*pi/5, 4*pi/5, 6*pi/5, or
8*pi/5. Each of these points is a unit distance from the origin, and they
form a regular pentagon. In general, the solution set of z^n = 1,
where n = 3, 4, . . . , consists of n points, each of unit distance from
the origin, forming a regular n-gon with z = 1 + 0*i being one of the
points.
I don't understand it though.
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Old 12-08-2005, 05:45 AM   #6
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I call the z axis the magical axis... the y axis is the value axis... x axis is power or something.

I think a real king/queen (rulers are valuable) = an imaginary joker (jokers are funny but worthless)

so x=1,z=1 = x=-1,z=-1
or ni = --ni ???
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Old 12-08-2005, 05:59 AM   #7
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Four No-Trump
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Old 12-08-2005, 06:24 AM   #8
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another james bond who thinks in the area of magic (reality/indeterminate/fantasy) who lacks value (out of true/false, is false) and primary morality is morality of 2 = avoid pain (magical thinking is noisy!)
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Old 12-08-2005, 06:34 AM   #9
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Old 12-08-2005, 06:35 AM   #10
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well I'm the computer mind now, I think I'll play another game soon, maybe the magic game or the value (rich/indeterminate/worthless) game...

hmm... life is a game... by me doing this I am jumping from one combination to another... this is confusing... deja vu (I was thinking that !) anyway, I think I'll keep on being the computer mind doing the links until I think I'm finished - that would involve searching around and getting back where I came from...

When I used to make computer games I had an idea of making a virtual world... there seems to be a pattern to going from one position on the matrix to another... x1,y1,z1 to x2,y2,z2 has some values for x1,y1,z1 and x2,x2,x2

kabalarians.com has the formulas for sale to find out how to get from one position to another....
can be bought or hacked...

Well you should now how to play the game now... it goes from one concept in the matrix to another, there is only one definite way from one concept to another. To have free will just use some magic - just reverse your magical feeling to its opposite.

Well I think you're figured it all out now... the matrix is 3x9x3, and is binary
= 2^(3x9x3)......... 2^81 = 2417851639229258349412352?

magic = indetermine value and morality
morality = indetermine magic and value
value = indeterminate value and morality

I choose magic for now...
I'll just do a google search
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