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Old 03-18-2004, 01:04 AM   #11
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Several people have mentioned proof by contradiction. The basic idea is that in order to prove P, show that ~P leads to a contradiction. In mathematical philosophy, the intuitionist (also called the constructivist) school does not accept this as valid reasoning. I don't agree with them, but I think it's important to note that not all mathematicians agree on what constitutes a valid proof.

A famous example of this method is the standard proof that the square root of 2 is irrational:

Suppose that sqrt (2) is rational. Then there exists integers p and q, such that p and q are relatively prime (they have no common factors), q is non-zero, and p/q =sqrt(2) => p^2/q^2 = 2 => p^2 = 2q^2 => p^2 is even, and thus p is even. Therefore there exists an integer n such that 2n = p, hence (2n)^2 = 2q^2 => 2n^2 = q^2 => q^2 is even, and thus q is even. But p and q cannot both be even since they are relatively prime, a contradiction. Therefore sqrt (2) is irrational.
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Old 03-18-2004, 10:44 AM   #12
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Quote:
Originally posted by Jet Black
Bear in mind Godel's Incompleteness Theorem as well. It doesn't impact directly on what anyone here has said so far, but put really roughly it states that any consistent, formal axiomatic system cannot prove it's own consistency.
Just to be a very broad pedant, it actaully says that any formal axiomatic system that is sophisticated enough to encode arithmetic either admits a statement, S, for which neither S nor not S is provable, or it admits a statement S for which both S and not S is provable.
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