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Old 12-07-2004, 08:09 AM   #1
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Default Math question (Laplace Transforms)

OK, so I can get sine transforms. How do I do a cosine transform?!

also...
sin at = [e^(ait) - e^(-ait)]/2i
cos at = [e^(ait) + e^(-ait)]/2i
...right?

Cramming for an exam, figured I'd post this in a place with a high geek concentration.
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Old 12-07-2004, 08:15 AM   #2
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Took Laplace transforms in college 45 years ago...wish I could help, but at my age I can't remember what I had for breakfast.....

Good luck on the exam!!
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Old 12-07-2004, 08:16 AM   #3
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I'll get my books and look, but if you repost this in S&S you'll have an answer in about ten minutes.

Ed
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Old 12-07-2004, 08:27 AM   #4
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Quote:
Originally Posted by nermal
I'll get my books and look, but if you repost this in S&S you'll have an answer in about ten minutes.

Ed
Good idea, thanks!
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Old 12-07-2004, 08:43 AM   #5
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Quote:
Originally Posted by Stiletto One
OK, so I can get sine transforms. How do I do a cosine transform?!

also...
sin at = [e^(ait) - e^(-ait)]/2i
cos at = [e^(ait) + e^(-ait)]/2i
...right?

Cramming for an exam, figured I'd post this in a place with a high geek concentration.
You're almost right. According to my engineering math book, Euler's formula gives

sin(at)=[e^(ait)-e^(-ait)]/2i
cos(at)=[e^(ait)+e^(-ait)]/2
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Old 12-07-2004, 08:54 AM   #6
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Eh, I've forgotten all that stuff. One thing that I didn't forget -- because I never had it explained to me such that I could understand it -- was why Laplace transforms (and inverse transforms) work.

Why can you take a differential equation, do a LaPlace transform -- transforming it into an algebra problem -- (wander around aimlessly in algebra-land for awhile until you hopefully stumble onto something you recognize ) -- do the reverse transform and magically get the solution to the differential equation.

Hells bells, I've forgotten so much that I'm not really sure if the above is a coherent summary of the process.
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Old 12-07-2004, 09:01 AM   #7
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You're effectively working the problem in a different space, then bringing it back into the original space solved.

Ed
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Old 12-07-2004, 09:07 AM   #8
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Quote:
Originally Posted by nermal
You're effectively working the problem in a different space, then bringing it back into the original space solved.

Ed
Well, yeah, I know that, but why does it work. Why can you change the problem space like that? It's almost as mysterious as if you transformed the differential equation into a crossword puzzle, solve the crossword puzlle, thinking "well, I don't know how to solve this differential equation, but I have these magic rules to change it into a crossword puzzle, and I know how to do crossword puzzles", then transform the solved crossword puzzle back into the solution of the diff. eq. via some more magic rules. (Ok, not quite that extreme, but almost that mysterious.) I suspect I no longer have the math background necessary to understand even a very good explanation.
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Old 12-07-2004, 10:07 AM   #9
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Default ^^^

Yeh, our teacher calls it "do the laplace transform, do some algebra, and do the inverse". That's about it.

I doubt I could get my brain around the theory if I tried for a year.
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Old 12-07-2004, 02:05 PM   #10
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Quote:
Well, yeah, I know that, but why does it work. Why can you change the problem space like that? It's almost as mysterious as if you transformed the differential equation into a crossword puzzle, solve the crossword puzlle, thinking "well, I don't know how to solve this differential equation, but I have these magic rules to change it into a crossword puzzle, and I know how to do crossword puzzles", then transform the solved crossword puzzle back into the solution of the diff. eq. via some more magic rules. (Ok, not quite that extreme, but almost that mysterious.) I suspect I no longer have the math background necessary to understand even a very good explanation.
Well maybe think of something simpler besides differential equations, like integrals ;-)

Solve the following integral: int(xe^(x^2).

Can't do it, unless you use substituition.

Damn, I wish this forum had the ability to imbed [tex] tags like they do over at physicsforums.org.
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